log[2](3+8x)-log[2](2x-1)=3

Solution for log[2](3+8x)-log[2](2x-1)=3 equation:

Simplifying
log[2](3 + 8x) + -1log[2](2x + -1) = 3

Reorder the terms for easier multiplication:
2glo(3 + 8x) + -1log[2](2x + -1) = 3
(3 * 2glo + 8x * 2glo) + -1log[2](2x + -1) = 3
(6glo + 16glox) + -1log[2](2x + -1) = 3

Reorder the terms:
6glo + 16glox + -1glo * 2(-1 + 2x) = 3

Reorder the terms for easier multiplication:
6glo + 16glox + -1 * 2glo(-1 + 2x) = 3

Multiply -1 * 2
6glo + 16glox + -2glo(-1 + 2x) = 3
6glo + 16glox + (-1 * -2glo + 2x * -2glo) = 3
6glo + 16glox + (2glo + -4glox) = 3

Reorder the terms:
6glo + 2glo + 16glox + -4glox = 3

Combine like terms: 6glo + 2glo = 8glo
8glo + 16glox + -4glox = 3

Combine like terms: 16glox + -4glox = 12glox
8glo + 12glox = 3

Solving
8glo + 12glox = 3

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-3 + 8glo + 12glox = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 8glo + 12glox = 0

The solution to this equation could not be determined.